1000 mL of HCl contains 0·75 mol                                 = 0.75 x 36.5                                 = 27.375 g   25 mL of HCl contains                                         = 0.684 gThe reaction isCaCO3(s)    +   2HCl(aq)    CaCl2(aq) + CO2(g) + H2O(l)1 mol                 2 mol40+12+48          2 x 36.5 = 100 g              = 73 g?                        0.684 g    Now 73 g of HCl are required to react with 100g of CaCO3     0.684 g of HCl are required to react with